How do you approach Solutions & Suspensions examination questions asking you to compare the solubility of different solutions?<\/p>\n
In this blog post, I will be sharing with you the following key points:<\/p>\n
- \n
- How you can convert the different volumes of solvent to 1 \u2113<\/li>\n
- How to find the corresponding amount of solute that can be dissolved in 1 \u2113 to compare the solubility of the different solutions<\/li>\n<\/ul>\n
Let\u2019s analyse this question on the topic of Solutions & Suspensions<\/strong> from the 2018 Geylang Methodist School (Secondary) (GMSS) S1(E) SA2 Examination Paper<\/strong>.<\/p>\n
Alternatively, you can watch our explainer video on this question here<\/a>.<\/p>\n
![\"\"](\"https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2024\/06\/science-made-simple-ep1-solution-400x225.jpg\")
<\/a><\/p>\n<\/p>\n
\nRead Also:<\/h3>\n
- \n
- [Secondary 1 Science Explainer Video] Solutions & Suspensions: How Is Solubility Tested In Chemistry Examinations<\/a><\/strong><\/li>\n
- Algebra: How To Simplify Algebraic Fractions<\/b><\/a><\/li>\n<\/ol>\n<\/div>\n
Let’s Take A Look At This Solutions & Suspensions Question<\/h2>\n
![\"\"](\"https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2024\/06\/18S1ESA2_GMSS_CHEM_Q5-01-1024x414.png\")
<\/p>\nSource: Geylang Methodist School (Secondary) \u2013 2018 S1E SA2 Examination Paper [Q5]<\/span><\/em><\/p>\n\n
Let us begin by reading the question.<\/p>\n
At 25\u00b0C, salt has a solubility of 360 g\/\u2113 in water<\/em>.<\/p>\n
\n
\ud83e\uddea\u00a0What Does Solubility Mean?<\/strong> \ud83e\uddea<\/p>\n
It means that if you have 1 \u2113 of water, a maximum of 360 g of salt can be dissolved at 25\u00b0C.<\/p>\n<\/blockquote>\n
So, we are looking at which of the following options will produce a saturated salt solution without any excess salt when mixed<\/strong>.<\/p>\n
In this case, you have the maximum amount of the salt that is dissolved in the solvent and you don\u2019t want any extra salt to be left behind undissolved.<\/p>\n
When you look at the options, you will see different volumes of water.<\/p>\n
\n
\ud83d\udca1\u00a0Trick To Answer Solubility Questions<\/strong> \ud83d\udca1<\/p>\n
The trick is to convert the different volumes of water to 1 \u2113 and find the corresponding amount of salt that is dissolved in that 1 \u2113 of water.<\/p>\n<\/blockquote>\n
<\/p>\n
Let’s Analyse Option (1)<\/h2>\n
![\"\"](\"https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2024\/06\/18S1ESA2_GMSS_CHEM_Q5-02-400x40.png\")
<\/p>\nSource: Geylang Methodist School (Secondary) \u2013 2018 S1E SA2 Examination Paper [Q5]<\/span><\/em><\/p>\n
You have 180 g of salt dissolved in 2000 ml of water.<\/p>\n
2000 ml is equivalent to 2 \u2113 of water. If you were to convert that to 1 \u2113 of water, you would have to divide both values by 2.<\/p>\n
We will then get 90 g of salt dissolved in 1 litre\u00a0of water<\/strong>.<\/p>\n
![\"\"](\"https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2024\/06\/18S1ESA2_GMSS_CHEM_Q5-03-400x40.png\")
<\/strong><\/p>\nSource: Geylang Methodist School (Secondary) \u2013 2018 S1E SA2 Examination Paper [Q5]<\/span><\/em><\/p>\n
Let’s Analyse Option (2)<\/h2>\n
![\"\"](\"https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2024\/06\/18S1ESA2_GMSS_CHEM_Q5-04-400x52.png\")
<\/p>\nSource: Geylang Methodist School (Secondary) \u2013 2018 S1E SA2 Examination Paper [Q5]<\/span><\/em><\/p>\n
For Option 2, we have 720 g of salt dissolved in 500 ml of water.<\/p>\n
To convert this to 1 \u2113, you have to multiply both values by 2.<\/p>\n
This would give you 1,440 g of salt dissolved in 1 litre of water<\/strong>.<\/p>\n
![\"\"](\"https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2024\/06\/18S1ESA2_GMSS_CHEM_Q5-05-400x52.png\")
<\/p>\nSource: Geylang Methodist School (Secondary) \u2013 2018 S1E SA2 Examination Paper [Q5]<\/span><\/em><\/p>\n
<\/p>\n
Let’s Analyse Option (3)<\/h2>\n
![\"\"](\"https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2024\/06\/18S1ESA2_GMSS_CHEM_Q5-06-400x50.png\")
<\/p>\nSource: Geylang Methodist School (Secondary) \u2013 2018 S1E SA2 Examination Paper [Q5]<\/span><\/em><\/p>\n
Again, we have 500 ml of water, so let us multiply both values by 2.<\/p>\n
It will give us 360 g of salt dissolved in 1 litre of water<\/span><\/strong>.<\/p>\n
<\/p>\n
![\"\"](\"https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2024\/06\/18S1ESA2_GMSS_CHEM_Q5-07-400x50.png\")
<\/p>\nSource: Geylang Methodist School (Secondary) \u2013 2018 S1E SA2 Examination Paper [Q5]<\/span><\/em><\/p>\n
Let’s Analyse Option (4)<\/h2>\n
![\"\"](\"https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2024\/06\/18S1ESA2_GMSS_CHEM_Q5-08-400x48.png\")
<\/p>\nSource: Geylang Methodist School (Secondary) \u2013 2018 S1E SA2 Examination Paper [Q5]<\/span><\/em><\/p>\n
For option (4), we have 720 g of salt dissolved in 3000 ml of water, which is equivalent to 3 \u2113 of water.<\/p>\n
You have to divide both values by 3, so you will get 240 grams of salt dissolved in 1 litre of water<\/strong>.<\/p>\n
<\/p>\n
![\"\"](\"https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2024\/06\/18S1ESA2_GMSS_CHEM_Q5-09-400x50.png\")
<\/p>\nSource: Geylang Methodist School (Secondary) \u2013 2018 S1E SA2 Examination Paper [Q5]<\/span><\/em><\/p>\n
Thought Process<\/h2>\n
Now that we have converted the volumes of water to 1 \u2113, it is easier for us to compare the mass of salt that can be dissolved in 1 \u2113 of water.<\/p>\n
![\"\"](\"https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2024\/06\/18S1ESA2_GMSS_CHEM_Q5-10-1024x273.png\")
<\/p>\nSource: Geylang Methodist School (Secondary) \u2013 2018 S1E SA2 Examination Paper [Q5]<\/span><\/em><\/p>\n
For option (1), we have 90 g of salt dissolved in 1 \u2113 of water. Will this give us a saturated salt solution at 25\u00baC?<\/p>\n
No, because we need 360 g of salt in 1 \u2113 of water. Option (1) is out<\/strong>.<\/p>\n
What about option (2) \u2014 1440 g of salt dissolved in 1 \u2113 of water?<\/p>\n
There will be an excess because only 360 g will be dissolved in 1 \u2113 of water. All the extra salt will remain undissolved. Is this what the question wants? No! The question wants a saturated solution without any excess salt. This option is also out<\/strong>.<\/p>\n
Next, let us check option (3). It shows the maximum amount of salt that can dissolve at 25\u00b0C. This is our answer<\/strong>!<\/p>\n
However, let us still check option (4).<\/p>\n
When we dissolve 240 g of salt in 1 \u2113 of water, are we going to get a saturated salt solution? No, this amount is insufficient<\/strong>.<\/p>\n
![\"\"](\"https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2024\/06\/18S1ESA2_GMSS_CHEM_Q5-11-1024x251.png\")
<\/p>\nSource: Geylang Methodist School (Secondary) \u2013 2018 S1E SA2 Examination Paper [Q5]<\/span><\/em><\/p>\n
This confirms that our answer is Option (3)<\/span><\/strong>.<\/p>\n
<\/p>\n
Conclusion<\/h2>\n
To recap, when faced with Solutions & Suspensions questions like above, remember to convert the different volumes of water to 1 \u2113 and find the corresponding amount of salt that is dissolved in that 1 \u2113 of water first.<\/p>\n
Doing this will make it easier for you to compare the mass of salt that can be dissolved in 1 \u2113 of water.<\/p>\n
Stay tuned for more Chemistry blog posts!<\/p>\n
<\/p>\n
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- Algebra: How To Simplify Algebraic Fractions<\/b><\/a><\/li>\n<\/ol>\n<\/div>\n
- [Secondary 1 Science Explainer Video] Solutions & Suspensions: How Is Solubility Tested In Chemistry Examinations<\/a><\/strong><\/li>\n