Today, I’d like to discuss some answering techniques that can be used to tackle questions on Evaporation<\/strong>.<\/p>\n At the primary school level, evaporation is known as the process by which water changes from a liquid state (water) to a gaseous state (water vapor).<\/p>\n The main difference\u00a0between evaporation and boiling is that evaporation occurs at all temperatures but boiling only occurs at 100\u02daC<\/span>.<\/p>\n There are four factors of evaporation, namely<\/span>:<\/strong><\/p>\n <\/p>\n <\/p>\n In the above question, we’re looking specifically at the effect of exposed surface area on the rate of evaporation.<\/p>\n This question requires students to arrange the containers\u00a0according to the volume of water left in each container, from the least to the most.<\/p>\n This means that students have to arrange them based on the order of descending rates of evaporation<\/span>.<\/p>\n One important point to note is that the rate of evaporation is dependent on the exposed surface area of the water in contact with the air<\/span>, and NOT\u00a0the size of the mouth of the containers.<\/p>\n Thus, the focus should only be on the value of \u201cb”<\/span>, which is the surface area of the water exposed to air.<\/p>\n With the above thought\u00a0process in mind, we are able to observe that the container with the largest \u201cb\u201d value is W and the container with the smallest \u201cb\u201d value is Y. This means that the answer would be W, __ , __ , Y.<\/p>\n <\/p>\n In order to fill in the two blanks above with X and Z, we will need to shift our focus to the shape of the container.<\/p>\n The exposed surface area of the water in container X will not change as the water level decreases because of its straight walls<\/span>. Thus, the rate of evaporation of the water in Container X is constant<\/span>.<\/p>\n In contrast, the walls of Container Z is slanted<\/span>. This means that the exposed surface area of the water increases as the water level decreases. This suggests that the rate of evaporation in Container Z would increase over time<\/span>.<\/p>\n Thus, the rate of evaporation of water in container Z is faster than the rate of evaporation of water in container X.<\/p>\n <\/p>\n Thus, the answer to this question is Option (2) \u2013 W, Z, X, Y<\/span>.<\/p>\n [\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row admin_label=”CCI” _builder_version=”4.16″ custom_margin=”0px||” custom_padding=”0px||” global_colors_info=”{}”][et_pb_column type=”4_4″ _builder_version=”4.16″ custom_padding=”|||” global_colors_info=”{}” custom_padding__hover=”|||”][et_pb_divider color=”#898989″ _builder_version=”4.16″ locked=”off” global_colors_info=”{}”][\/et_pb_divider][et_pb_image src=”https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2019\/05\/The-Pique-Lab-CCI-Science-Course-CTA.png” align=”center” align_tablet=”center” align_phone=”” align_last_edited=”on|desktop” admin_label=”CCI” _builder_version=”4.16″ z_index_tablet=”500″ global_colors_info=”{}”][\/et_pb_image][et_pb_text _builder_version=”4.16″ text_font=”||||||||” text_text_color=”#333333″ text_font_size=”18px” text_orientation=”center” global_colors_info=”{}”]<\/p>\n If you like our methodology, we’ve some upcoming workshops:<\/p>\n [\/et_pb_text][et_pb_text _builder_version=”4.16″ text_font=”geomanist-medium||||||||” text_text_color=”#f44a4a” text_font_size=”18px” text_orientation=”center” global_colors_info=”{}”]<\/p>\n P4 Complete Concept Integration\u2122 Science Course<\/strong><\/a> [\/et_pb_text][\/et_pb_column][\/et_pb_row][\/et_pb_section]<\/p>\n","protected":false},"excerpt":{"rendered":" <\/p>\n","protected":false},"author":6,"featured_media":241542,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_et_pb_use_builder":"on","_et_pb_old_content":"Students learn<\/span> the topic of Electricity<\/strong><\/span>\u00a0at Primary 5 and many of them find the concepts to be confusing, especially when they are first exposed to this topic.\r\n\r\nAs such, over the next few blog posts, I will be sharing more about the concepts of Electricity<\/strong><\/span>\u00a0that are commonly tested during examinations.\r\n\r\nIn today\u2019s blog post, I will be focusing on the arrangement of the wires in a bulb and relate it to how a bulb should be connected in a circuit.\r\n The following question is commonly encountered by students during tests.<\/p>\r\n Example of a circuit when the wires are connected only to the metal tip<\/em><\/p>\r\nWhen both wires are connected to the metal tip of the bulb, electricity is unable to flow through the filament, preventing the bulb from lighting up.\r\n\r\nScenario #2: Both wires are connected to the metal casing<\/strong><\/span>\r\n\r\n\u00a0\r\n Circuit A<\/strong><\/span><\/p>\r\n Circuit B<\/strong><\/span><\/p>\r\n Circuit C<\/strong><\/span><\/p>\r\nWhat Your Child Needs To Know<\/span><\/h2>\n
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Read Also<\/span><\/h2>\n
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Question<\/span><\/h2>\n
![\"\"](\"https:\/\/thepiquelab.com\/blog\/wp-content\/uploads\/2016\/07\/Screen-Shot-2018-08-02-at-4.24.05-PM.png\")
<\/p>\nThought Process<\/span><\/h2>\n
Next Step<\/span><\/h3>\n
Final Answer<\/span><\/h2>\n
P5 Complete Concept Integration\u2122 Science Course<\/strong><\/a>
P6 Complete Concept Integration\u2122 Science Course<\/strong><\/a><\/p>\nToday\u2019s Question:<\/span><\/h2>\r\n
How Should The Bulb Be Connected To The Circuit For It To Light Up?<\/strong><\/span><\/blockquote>\r\n
![\"\"](\"https:\/\/thesmartstudent.sg\/wp-content\/uploads\/2017\/09\/ACS-J-Question-1024x630.png\")
<\/a>Question Credit: Anglo Chinese School (Junior)\/ 2015 Primary 5 SA1\/ Question 18<\/em><\/p>\r\nWe can see that the key difference between the four options is the connection of the bulb(s) in the circuit.\r\nRequirements Needed for a Bulb to Light Up<\/span><\/strong><\/h3>\r\n\u00a0\r\n\r\n
![\"\"](\"https:\/\/thesmartstudent.sg\/wp-content\/uploads\/2017\/09\/Screenshot-2017-09-17-12.54.25-1024x547.png\")
<\/a>\r\n\r\n\u00a0\r\n\r\nOne wire is connected to the metal casing & one wire is connected to the metal tip<\/u><\/strong>\r\n\r\n\u00a0\r\n![\"\"](\"https:\/\/thesmartstudent.sg\/wp-content\/uploads\/2017\/09\/Example-of-a-Closed-Circuit-e1505630926957-1024x665.png\")
<\/a>Example of a closed circuit<\/em><\/p>\r\nWhen the wires in the circuit are connected to the metal casing and metal tip of the bulb, there is a closed (or complete) circuit with the bulb. Electricity will be able to flow through the filament, causing the bulb to light up.\r\nWhat Happens When Both Wires Are Connected To The Metal Tip\/Metal Casing?<\/strong><\/span><\/h2>\r\nScenario #1: Both wires are connected to the metal tip<\/strong><\/span>\r\n\r\n
![\"\"](\"https:\/\/thesmartstudent.sg\/wp-content\/uploads\/2017\/09\/Scenario-1-e1506494508837-1024x543.png\")
<\/a>\r\n![\"\"](\"https:\/\/thesmartstudent.sg\/wp-content\/uploads\/2017\/09\/Scenario-2-e1505630899322-1024x545.png\")
<\/a>Example of a circuit when the wires are connected only to the metal casing<\/em><\/p>\r\nWhen both wires are connected to the metal casing of the bulb, electricity is unable to flow through the filament, preventing the bulb from lighting up.\r\n\r\nNow, let us now take a look at the question again.\r\nAnalysis Of The Options<\/strong><\/span><\/h2>\r\n
<\/a>\r\n\r\nWhen analysing the circuits, students need to take note of one key point:\r\nHow is the bulb connected to the circuit?<\/strong><\/span><\/h3>\r\nIn the following analysis, I have traced the pathway that electricity flows through (in red) as well so that it is easier to understand why the bulb lights up.\r\n
![\"\"](\"https:\/\/thesmartstudent.sg\/wp-content\/uploads\/2017\/09\/Circuit-A-748x1024.png\")
<\/a>\r\n\r\nBoth the metal casing and tip of the bulb are connected to the circuit, forming a closed circuit. Thus, electricity is able to flow through the wires in the circuit to the filament, allowing the bulb to light up.\r\n![\"\"](\"https:\/\/thesmartstudent.sg\/wp-content\/uploads\/2017\/09\/Circuit-B-940x1024.png\")
<\/a>\r\n\r\nOnly the tip is connected to the circuit. Thus, electricity is unable to flow through the filament, preventing the bulb from lighting up.\r\n
![\"\"](\"https:\/\/thesmartstudent.sg\/wp-content\/uploads\/2017\/09\/Circuit-C-1024x819.png\")
<\/a><\/p>\r\nOnly the casing is connected to the circuit. Thus, electricity is unable to flow through the filament, preventing the bulb from lighting up.\r\n![\"\"](\"https:\/\/thesmartstudent.sg\/wp-content\/uploads\/2017\/09\/Circuit-D-707x1024.png\")
<\/a><\/p>\r\nBoth the metal casing and tip of the two bulbs are connected to the circuit, forming a closed circuit. Thus, electricity is able to flow through the wires in the circuit to the filaments, allowing the bulbs to light up.\r\n\r\nAs the bulbs in circuits A and D will light up, the correct answer is option 4.\r\n